sqlalchemy联合查询两个表的数据,
查询Subject表所有数据,如果Subject有对应的Lesson数据就显示出来,没有就不显示
subjects = self.db.query(Subject.id, Subject.name, Subject.level,
Subject.children, Lesson.id.label('lesson'))
.outerjoin((Lesson, Subject.id==Lesson.subject_id))
.order_by(Subject.level).all()
注:效率很低